Please answer and show all work and units. Will rate ASAP. ---------------------
ID: 1068302 • Letter: P
Question
Please answer and show all work and units. Will rate ASAP.-------------------------------------------------------------------------------------------------------
Consider the reaction shown below taking place at 25oC
N2(g) + 3 H2 (g) 2 NH3 (g)
For this reaction it has been found that Horx = - 92.38 kJ and Sorx= - 98.4 J/K
A) Calculate the value of Gorx. Is this reaction spontaneous? Why or why not?
B) Calculate the value of the equilibrium constant, Kp, for this reaction. In which direction is the equilibrium displaced?
------------------------------------------------------------------------------------------------------- Please answer and show all work and units. Will rate ASAP.
-------------------------------------------------------------------------------------------------------
Consider the reaction shown below taking place at 25oC
N2(g) + 3 H2 (g) 2 NH3 (g)
For this reaction it has been found that Horx = - 92.38 kJ and Sorx= - 98.4 J/K
A) Calculate the value of Gorx. Is this reaction spontaneous? Why or why not?
B) Calculate the value of the equilibrium constant, Kp, for this reaction. In which direction is the equilibrium displaced?
------------------------------------------------------------------------------------------------------- Please answer and show all work and units. Will rate ASAP.
-------------------------------------------------------------------------------------------------------
Consider the reaction shown below taking place at 25oC
N2(g) + 3 H2 (g) 2 NH3 (g)
For this reaction it has been found that Horx = - 92.38 kJ and Sorx= - 98.4 J/K
A) Calculate the value of Gorx. Is this reaction spontaneous? Why or why not?
B) Calculate the value of the equilibrium constant, Kp, for this reaction. In which direction is the equilibrium displaced?
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Explanation / Answer
Answer – A) We are given the, Horxn = -92.38 kJ , Sorxn = -98.4 J/K
T = 25+273.15 = 298.15 K
we know formula
Gorxn = Horxn -T*Sorxn
We need to convert the Horxn kJ to J
We know,
1 kJ = 1000 J
So, -92.38 = ?
= -92380 J
Gorxn = -2380 J/mol – 298.15 K * -98.4 J/mol.K
= -63042.04 J/mol
= -63.042 kJ/mol
So the standard Gibb’s free energy is negative, so reaction is spontaneous .
B ) Now equilibrium constant
Go = -RTlnKp
So, -63042.04 J = - 8.314 J/mol.K * 298.15 K * ln Kp
ln Kp = -63042.04 J / - 8.314 J/mol.K * 298.15 K
= 25.43
Taking antiln from both side
Kp = 1.11*1011
According to Kp value we confirmed that direction is the equilibrium displaced is towards right side or product side.