Mg(s) + Pb^2+(aq) rightarrow Mg^2+(aq) + Pb(s) For the above reaction, the catho

Question

Mg(s) + Pb^2+(aq) rightarrow Mg^2+(aq) + Pb(s) For the above reaction, the cathode electrode _____; and the anode electrode ________. must be Pb; must be Mg must be Mg: must be Pb may be an inert material; must be Mg must be Pb; may be an inert material must be Mg; may be an inert material Mg(s) + Pb^2+(aq) rightarrow Mg^2+(aq) + Pb(s) If the above galvanic cell starts at standard slate conditions, ______. E increases because Q increases. E decreases because Q decreases. E increases because Q decreases. E decreases because Q increases.

Explanation / Answer

0 +2 +2 0

Mg(s) + Pb2+ (aq) ----> Mg2+(aq) + Pb(s)

Here the oxidation state of Mg increases so oxidation takes place it happens at anode is Mg & the cathode is inert material

Therefore option (C) is correct.

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WE know that delta G = -nFEo

Also delta G = -RT ln Q

So nFEo = RT lnQ

AS Q increases ln Q increases and Eo is proportional to ln Q so Eo also increases

Therefore option (A) is correct

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