I have no idea what to do for this problem despite the answer key \"explaining\"

Question

I have no idea what to do for this problem despite the answer key "explaining" it somewhat. Please show and tell me step by step what to do as if explaining to somebody who never took chemistry before. I don't understand how to write a rate law nor how to get subscripts for the chemical equations so please write and explain how to me.

4. (12 points) When consuming ethanol, it is important to avoid contact with sodium metal due to the production of highly flammable hydrogen gas in the following reaction: 2 CH3CH2OH (l) 2 Na (s) 2 CH3CH2ONa (s) H2 (g) In order to determine the kinetics of the reactions the following experiments were conducted Trial ICH3CH20HICM) Nal (M Rate (M/min) 0.10 1.5 x 10 0.12 2xC OX 3.0 x 10 UX 0.24 0.10 0.12 0.20 1.2 x 10 a) Write the rate law for the reaction. b) What is the rate constant for the reaction (be sure to include units)? he L0.12 L 0.1 in man I M 12.5 min Page Total

Explanation / Answer

4)
a)
see trial 1 and 2
[CH3CH2OH] doubles
[Na] is constant
rate also doubles
so,
order of CH3CH2OH is 1

see trial 1 and 3
[CH3CH2OH] constant
[Na] is doubles
rate become 8 times
so,
order of Na is 3

rate law is:
rate = k[CH3CH2OH] [Na]^3

b)
rate = k[CH3CH2OH] [Na]^3
put values from trial 1
1.5*10^-3 M/min = k (0.12M ) (0.10 M)^2
= 12.5 min-1M-2
Answer: 12.5 min-1M-2

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