An inhibitor of molecular weight of 483.5 is given to you as an accurately weigh

Question

An inhibitor of molecular weight of 483.5 is given to you as an accurately weighed sample of 9mg dry powder. You do not have access to a balance. But you still need to prepare a stock solution of 0.75mM Inhibitor. What do you do? List your answer in numbered steps, ie step 1 - do this, step 2 -do this etc. Be sure to give all amounts needed to prepare the solution. Factors will be considered included correctness, clarity, and conciseness. sewer questions: 7 points each. Factors that will be considered include correctness, clarity and conciseness. Please that was asked to be considered for most points. re there conditions under which both DNA and protein denature? Explain.

Explanation / Answer

MW of the inhibitor = 483.5 g

Mass of the sample powder = 9 mg = 0.009g

So moles of inhibitor present in the sample = Sample mass/MW = 1.861*10-5 moles = 1.861*10-2 milli moles

Required concentration = 0.75 mM = 0.75 milli moles/L

Since molarity = moles/Volume in Liters

So, Volume = moles/Molarity = 1.861*10-2/0.75 = 2.481*10-2 L = 24.81 mL

Thus, we can prepare the stock solution of 0.75 mM inhibitor by dissolving the 9 mg powder sample in 24.81 mL of water. We don't need any balance for this because we are using the whole amount of powder, we just need to accurately measure out the volume of water required to prepare the solution of desired conc.

Hope this helps ! Ask if you have any other queries.

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