For the electrochemical cell, Fe(s)|Fe^2+ (aq)||Cu^2+(aq)|Cu^+(aq)|Pt(s), determ
ID: 1073790 • Letter: F
Question
For the electrochemical cell, Fe(s)|Fe^2+ (aq)||Cu^2+(aq)|Cu^+(aq)|Pt(s), determine the equilibrium constant (K_eq) at reaction that occurs. 1.6 times 10^-10 8.6 times 10^19 1.2 times 10^-20 9.3 times 10^9 1.3 times 10^-5 Which of the following is consistent with a reaction that proceeds spontaneously in the reverse direction (assume all of the forward direction only)? G > 0, Q 0, Q = K G > 0, Q > K Which of the following processes would be accompanied by increase in entropy? O(g) rightarrow H_2O(s) O(l) rightarrow H_2O(s) O(g) rightarrow H_2O(l) O(s) rightarrow H_2O(g) (l, 50 degree C) rightarrow H_2O(l, 25 degree C)Explanation / Answer
for the given cell, Fe---->Fe+2 +2e- Eo= -0.44V (1), Cu+2 +e- -------->Cu+ Eo= 0.153 V (2)
addition of Eq.1 and 2*Eq.2 gives Fe+2Cu+2---->2Cu+ +Fe+2 EO= -0.281V
deltaG= -nFE= 0.103**96500
nFE= RTlnK
lnK= nEF/ RT, n= number of electrons exchanged, E= -0.103V, T=298K, F =96500
lnK= -0.281*96500*2/(8.314*298)
K= 1.952*10-10 ( A is correct)
2. A process is spontaneous in the forward directino if deltaG<0 and Q<K. Hence in thereverse direction if deltaG> 0 and Q>K, the process is spontaneous. E is correct
3. Entropy is degree of disorder. Hence entropy increase leads to increase in disorder. Hence solid when changes to gas become more disordered. D is correct
3.