For the double-loop circuit shown, use the junction rule and loop rule to come u
ID: 1612228 • Letter: F
Question
For the double-loop circuit shown, use the junction rule and loop rule to come up with three equations that can be solved for the three currents. 6. Junction Rule (right junction) a. I_1 + I_2 + I_3 = 0 b. I_1 = I_2 + I_3 c. I_2 = I_1 + I_3 d. I_3 = I_1 + I_2 e. None of the above 7. Loop Rule for Upper Loop (clockwise from junction) a. -8 + 60I_3 - 120I_1 - 3 - 120I_1 = 0 b. -8 + 60I_3 + 120I_1 - 3 + 120I_1 = 0 c. -8 + 60I_2 - 120I_3 - 3 + 120I_2 = 0 d. -8 + 60I_3 - 120I_1 + 3 + 120I_1 = 0 e. None of the above 8. Loop Rule for Lower Loop (counterclockwise from junction) a. 130I_2 + 60I_3 - 2 + 240i_2 + 8 = 0 b. -8 + 60I_3 - 2 + 240I_2 + 130I_2 = 0 c. -8 - 60I_3 - 2 - 240I_2 - 130I_2 = 0 d. -8 + 60I_2 - 2 + 240I_3 + 130I_3 = 0 e. None of the aboveExplanation / Answer
6)
junction rule: sum of the incoming currents = sum of the outgoing current
I3 = I1 + I2
OPTION (d)
(7)
Loop rule
the algebraic sum of all emf's and potential difference across ressitors = 0
-8 + 60*I3 + 120*I1 - 3 + 120*I1 = 0
OPTION b
(8)
-8 + 60*I3 - 2 + 240*I2 + 130*I2 = 0
option (b)