Methane and water react to form carbon monoxide and hydrogen, like this: CH4(g)
ID: 1086637 • Letter: M
Question
Methane and water react to form carbon monoxide and hydrogen, like this: CH4(g) + 11,0(g) CO(g)" 3112(g) Imagine 118. mmol of CH4 and 118. mmol of H2O are added to an empty flask, and then answer the following questions Zero Greater than zero, but less than the rate of the reverse reaction Greater than zero, and equal to the rate of the reverse reaction Greater than zero, and greater than the rate of the reverse reaction Zero Greater than zero, but less than the rate of the reverse reaction Greater than zero, and equal to the rate of the reverse reaction Greater than zero, and greater than the rate of the reverse reaction What is the rate of the forward reaction before any CH4 or H20 has been added to the flask? What is the rate of the forward reaction just after the CH4 or H20 has been added to the flask? Zero What is the rate of the forward reaction at equilibrium? Greater than zero, but less than the rate of the reverse reaction Greater than zero, and equal to the rate of the reverse reaction Greater than zero, and greater than the rate of the reverse reaction None Some, but less than 118. mmol 118. mmol More than 118. mmol How much CH4 is in the flask at equilibrium?Explanation / Answer
a) Before any CH4,H20 is added to the flask, th rate of forward reactio is zero.Since there are no reactants for the reaction to occur.
b) When the reactants are just added to the flask,rate of forward reaction is greater than that of reverse reaction since there are only reactants for the forward reaction to occur.
c) At equilibrium,the rate of forward reaction is equal to the rate of reverse reaction.
d) At equilibrium,amount ofCH4 present in the flask is something less than 118 mmol (initial concentration) since some ofthe reactant will be consumed.