Methane and water react to form carbon monoxide and hydrogen, like this: CH4(g)+
ID: 584941 • Letter: M
Question
Methane and water react to form carbon monoxide and hydrogen, like this: CH4(g)+H2O(g) CO(g)+3H2(g) Suppose a mixture of CH4, H,O, CO and H, has come to equillbrium in a closed reaction vessel. Predict what cha below will cause in the composition of the mixture in the vessel. Also decide whether the equilibrium shifts to the ri perturbation change in composition shift in equilibrium O to the right to the left The pressure of CH, will Some H2O is removed. The pressure of CO will (none) to the right The pressure of CHa will? The pressure of H,o will to the left Some CO is added. (none) O to the right The volume of the vessel is The pressure of CHs will ? increased to the left The pressure of HO wll? (none)Explanation / Answer
The direction to which equilibrium shifts can be understood by Le'Chatlier's principle.
According to this when a system at equilibrium is subjected to a changes in either concentration of the substances or the pressure of the gaseous substrates or the temperature of the reaction,then the equilibrium will shift in such a direction that it nullifies the effect that is in the opposite direction of the change.
When some H2O is removed,then the equilibrium will shift towards left.
The pressure of CH4 will increase.
The pressure of CO(g) will decrease.
Some CO(g) is added,then equilibrium shift towards left.
The pressure of methane gas increases.
The pressure of water also increases.
When the volume of the vessel is increased, the equilibrium shift towards right.
Since in the forward direction volume of the product species carbon monoxide and hydrogen is more than the reactants.
The pressure of methane and water both will decrease.