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CHEM123-002-201840:did! d, University of Louisiana, × aplinglearning.com/ibi "php?id=4703418 ing rsity of Louisiana at Lafayette CHEM 123-Spring18- LEONARD > Activities and Due 2/19/2018 1 159 PM633/100 () 2/19/2018 os 28 PM Gradebook Question 3 of 6 Sapling Learning (a) How many grams of CsO2 are needed to make 192.1 g of a solution hat is 39.0% (mim) caloium chloride in water? Number R CaCI, 151 ml of isopropy alcohol in enough water to make 767 ml. of total solutionby dissv Number % (v/v) Check Answer Nest

Explanation / Answer

a) % m/m = (mass of solute / mass of solution) x 100

39.0 = (mass of solute / 192.1) x 100

0.039 = mass of solute / 192.1

mass of solute = 7.492 g

mass of CaCl2 = 7.492 g

b) % v/v = (volume of solute / volume of solution) x 100

% v/v = (151 / 767) x 100

% v/v = 19.69

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