Consider the estimated equation = 3, 586.38 - 0.151 totwrk n = 706 R2 = 0.103 (38.91) (0.017) where sleep is total minutes of sleep and totwrk is total minutes of work. The quantity in parentheses is the standard error of the estimated coefficient. Is totwrk significant at the 5% level? Explain. Construct a 95% confidence interval for the estimated coefficient on totwrk. Does 0 lie in the interval? Explain.
Explanation / Answer
1> the given R^2 =0.103 this means the regression model explains a 10.3%of regression hence the total work is significant at 5% level 2>95% confidence interval for tot work -0.151- t(0.025 , 704 )/0.017