Identify the osmolarity (Hyposmotic, isosmotic, or hyperosmotic), Tonicity (Hypo
ID: 12530 • Letter: I
Question
Identify the osmolarity (Hyposmotic, isosmotic, or hyperosmotic), Tonicity (Hypotonic, isotonic, hypertonic) and direction of net water movement , and the effect of water movement on the cells size?A) Intracelluar: 300 mOsm NaCI
B) Extracellar: 150 mOsm NaCI, 150 mOsm urea
A) Intracelluar: 300 mM NaCI
B) Extracelluar: 300 mM Glucose
A) Intracellar: 300 mOsm NaCI
B) Extracelluar: 150 mOsm NaCI and 150 mOsm urea
A) Intracelluar: 300 mOsm NaCI and 50 mOsm urea
B) Extracelluar: 400 mOsm NaCI and 50 mOsm urea
Please explain if you can alittle thank you,
Explanation / Answer
A) Intracelluar: 300 mOsm NaCIB) Extracellar: 150 mOsm NaCI, 150 mOsm urea
As NaCl is permeable and can cross the membrane, the solute molecules cross the membrane till the concentration inside and outside the cell are equal. As urea cannot cross the membrane, the overall concentration of solutes outside the cell is higher than the concentration of solutes inside the cell. Hence the extracellular solution is hyperosmotic. After osmosis, the concentration inside the cell would be 225 mOsm NaCl and the concentration outside the cell would be 150 mOsm of urea and 225mOsm of NaCl. Hence water moves out of the cell and the cell shrinks. With regard to tonicity, after osmosis, the situation is hypertonic. --------------------------------------- A) Intracelluar: 300 mM NaCI
B) Extracelluar: 300 mM Glucose In this case, both NaCl and glucose are permeable. Hence the solutes move till the concentration is equal on both sides of the membrane. After osmosis, the concentration on each side of the membrane would be 150 mM NaCl and 150 mM Glucose. With regard to tonicity, as the concentration of solutes on both sides of the membrane are equal, the situation is isotonic after osmosis. As both the solutes are permeable, the situation becomes isoosmotic. No water movement seen. No changes in cell shape and structure. ------------------------------------ A) Intracellar: 300 mOsm NaCI
B) Extracelluar: 150 mOsm NaCI and 150 mOsm urea This is the same as the first case. ------------------------------------ A) Intracelluar: 300 mOsm NaCI and 50 mOsm urea
B) Extracelluar: 400 mOsm NaCI and 50 mOsm urea
As NaCl is permeable, the solutes move till 350 mOsm are present on either side of the membrane. As 50 mOsm of urea are present on either side of the membrane, the concentration of solutes are equal. This makes the situation isotonic and isoosmotic. No water movement seen. No changes in cell shape and structure. With regard to tonicity, as the concentration of solutes on both sides of the membrane are equal, the situation is isotonic after osmosis. As both the solutes are permeable, the situation becomes isoosmotic. No water movement seen. No changes in cell shape and structure. ------------------------------------ A) Intracellar: 300 mOsm NaCI
B) Extracelluar: 150 mOsm NaCI and 150 mOsm urea This is the same as the first case. ------------------------------------ A) Intracelluar: 300 mOsm NaCI and 50 mOsm urea
B) Extracelluar: 400 mOsm NaCI and 50 mOsm urea
As NaCl is permeable, the solutes move till 350 mOsm are present on either side of the membrane. As 50 mOsm of urea are present on either side of the membrane, the concentration of solutes are equal. This makes the situation isotonic and isoosmotic. No water movement seen. No changes in cell shape and structure.