A metallic and straight thin wire (length 2A) rotates with a frequcny f in a pla

Question

A metallic and straight thin wire (length 2A) rotates with a frequcny f in a plane perpendicular to a uniform field B.

Using faraday's law develop using dimensional analysis an expression in terms of a,f, & b for the induced emf e between the center of the wire and one end of the wire (which is at a distance a from the center).

Let B = 0.1 mT , a = .1 m and f = 1 hz .

Find the induced voltage difference between the two opposing ends of the rotating metallic wire. you can use your eqn of a) be sure about the units'

include a picture please too

Explanation / Answer

Note that

EMF is in Volts, or J/C.

Thus, we must be able to produce this unit from a, f, and B.

We can do that by using

EMF = B f a^2   [ANSWER]

*****************

Using our formula,

EMF = 1.0*10^-6 V   [ANSWER]

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