In the AC circuit shown in the figure below, R = 70.0 Ohm and the output voltage

Question

In the AC circuit shown in the figure below, R = 70.0 Ohm and the output voltage of the AC source is deltaVmax sin wt. (a) If delta VR = 0.255 deltaVmax for the first time at t = 0.0090 s, what is the angular frequency of the source? Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully, rad/s (b) What is the next value of t for which AVR = 0.255 deltaVmax? Your response differs from the correct answer by more than 10%. Double check your calculations. S

Explanation / Answer

a) VR = Vmax sinwt = 0.255 Vmax    at t = 0.0090 sec

sin (w *0.0090) = 0.255

w*0.0090 = sin-1(0.255) = 0.258 rad

w = 28.65 rad/s

b) sin(wt) = 0.255

we get 0.255 at theta = 0.258 rad   after that we will get again at 2.88 rad .

so , wt = 2.88

t = 2.88 / 28.65 = 0.1 sec

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