A very long straight wire carrying an electric current is perpendicular to the x
ID: 1263672 • Letter: A
Question
A very long straight wire carrying an electric current is perpendicular to the x-y plane. The current has a value of 32.3 A and is directed in the +z (out of the page). At point 'p', the magnetic field B is represented by one of the arrows.
A) Calculate the magnitude of the B-field at 'p'.
ANS: 8.27 * 10^-5 T
B) Calculate the x-component of the B-field at 'p'.
Please help with B (Finding the x-comp)! I can not for the life of me figure it out.
Edit: The answer is not 6.353 * 10^-5 T or -6.353 * 10^-5 T I've tried those.
A very long straight wire carrying an electric current is perpendicular to the x-y plane. The current has a value of 32.3 A and is directed in the +z (out of the page). At point 'p', the magnetic field B is represented by one of the arrows. A) Calculate the magnitude of the B-field at 'p'. ANS: 8.27 * 10^-5 T B) Calculate the x-component of the B-field at 'p'. Please help with B (Finding the x-comp)! I can not for the life of me figure it out. Edit: The answer is not 6.353 * 10^-5 T or -6.353 * 10^-5 T I've tried those.Explanation / Answer
Here , the direction of field is T
Now , for finding the angle T makes with x -axis
as U and T makes the same angle
tan(theta) = 5/6
theta = 39.8 degree
Now , x -compoenent Bx = B*cos(theta)
Bx = 8.27 *10^-5 * cos(39.8)
Bx = 6.353 *10^-5 T
the x-component of the field is 6.353 *10^-5 T