An inductor is made from a copper ribbon that has been bent to form a tube with

Question

An inductor is made from a copper ribbon that has been bent to form a tube with two flat extensions, as shown. The width of the copper ribbon is i max, for the circuit increase, decrease, or remain the same as the case where the external field is zero? If it changes, by how much? vec{B}=(1frac{T}{s}t)widehat{k} piercing the inductor. Does the maximum current in the circuit, r = 10.0 cm, and the space between the flat extensions is negligible. Suppose that there is a magnetic field a = 20.0 cm, the radius of the tube is

Explanation / Answer

a) L = uN^2A/L..........here L = 20 cm........A = 3.14*10^2

PartB) current at any time, i(t) = I_max(1-exp(-R*t/L)),,,,,,,,,

,to reach one half pu

t i(t)= 1/2 * I_max, R= 10 and L=1.97x10-7 H, on solving you get

t= 1.36 X 10-8 sec   

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