In Fig. (a), a particle of charge +1 e is initially at rest at coordinate z = 25

Question

In Fig. (a), a particle of charge +1e is initially at rest at coordinate z = 25 nm on the dipole axis through an electric dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -25 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle ? that locates the particle. What is the magnitude of the dipole moment?
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In Fig. (a), a particle of charge +1e is initially at rest at coordinate z = 25 nm on the dipole axis through an electric dipole. (The origin of z is at the dipole center.) The particle is then moved along a circular path around the dipole center until it is at coordinate z = -25 nm. Figure (b) gives the work Wa done by the force moving the particle versus the angle ? that locates the particle. What is the magnitude of the dipole moment?

Explanation / Answer

We can calculate the electric field due to the electron at the dipole location.
E = kq/r^2 = 9E9*1.6022E-19/25E-9^2 = 2307168 V/m
Then (see ref.) the energy change deltaU = 4E-30J = 2Ep
==> dipole moment p = 4E-30/(2E) = 8.6686E-37 C-m

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