In Fig. 1, three particles are fixed in place and have charges q 1 = q 2 = +e an
ID: 2107741 • Letter: I
Question
In Fig. 1, three particles are fixed in place and have charges
q1 = q2 = +e and q3 = +2e. Distance a = 6.00 μm. What are the (a)
magnitude and (b) direction (relative to the positive x axis) of the net
electric field at point P due to the particles. If a fourth particle of mass
m = 2.7x10−30 kg and charge Q = −3e is placed at P, determine the (c)
magnitude and (d) direction of the net electrostatic force on the charge
Q. (e) What is the magnitude of the initial acceleration of the fourth
particle?
Explanation / Answer
Plzz post the diagram for solution. you can use Force between 2 charges =k*Q1*Q2/ Distance^2 and Electric field due to charge Q at distance r =k*Q/r^2