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Problem 18.52 During each cycle a reversible engine absorbs 2600J of heat from a

ID: 1266495 • Letter: P

Question

Problem 18.52

During each cycle a reversible engine absorbs 2600J of heat from a high-temperature reservoir and performs 2300J of work.

Part A

What is the efficiency of this engine?

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Part B

How much heat is exhausted to the low-temperature reservoir during each cycle?

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Part C

What is the ratio, ThTc, of the two reservoir temperatures?

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Problem 18.52

During each cycle a reversible engine absorbs 2600J of heat from a high-temperature reservoir and performs 2300J of work.

Part A

What is the efficiency of this engine?

e =

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Part B

How much heat is exhausted to the low-temperature reservoir during each cycle?

Qc = J

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Part C

What is the ratio, ThTc, of the two reservoir temperatures?

ThTc =

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Explanation / Answer

Effeciency = ( Work done / Heat added )

Efficiency = ( 2300/2600)

Efficiency = 0.8846

Efficiency = 88.46 %

Heat Exhausted = Heat added - wrok done

Heat exhausted = 2600 - 2300

Heat exhausted = 300 J

We know that

Efficiency = 1 - ( Tc / TH )

0.8846 = 1 - ( TC /TH )

Tc / Th = 0.1154

so Tc / Th = 0.1154

Th/ Tc = 8.6655

so

Th / Tc = 8.6655