A defibrillator passes a brief burst of current through the heart to restore nor

Question

A defibrillator passes a brief burst of current through the heart to restore normal beating. In one such defibrillator, a 56.1 Mu F capacitor is charged to 4.68 kV. Paddles are used to make an electrical connection to the patient's chest. A pulse of current lasting 1.0 ms partially discharges the capacitor through the patient. The electrical resistance of the patient (from paddle to paddle) is 207 Omega. Part 1 (a) What is the initial energy stored in the capacitor? 614 J Part 2 out of 5 (b) What is the initial current through the patient? A

Explanation / Answer

b.

initial current I = V/R

I = 4680/(207)

I = 22.608 Amps

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