Please walk me through it. 16) A rectangle of rigid wire carrying a current I is

Question

Please walk me through it.

16) A rectangle of rigid wire carrying a current I is placed in a uniform magnetic field B vector. Sections AB and CD of the wire rectangle have a length a, and sections BC and DA of the wire rectangle have a length b. Determine the magnitude and direction of the force on each section of the wire in terms of a, b, I, and B when the rectangle is oriented relative to B as shown. Calculate the magnitude of the net torque on the wire rectangle about the given axis of rotation in terms of a, b, I, and B when the rectangle is oriented relative to B as shown. This contraption can be used to make a simple electric motor.

Explanation / Answer

=======================================
magnetic force on a wire of length L in magnetic field B is F = ILB

here magnetic fuled on the side AD and BC is zero as their magntudes are equal but due to in opposite directions

there exists force of AB and CD , and these two constitutes force between two parallel wires

action iof field on this sides will differ in terms of magnetudes,

thus Fnet = FAB + FCD

Fnet = iaB + iaB

Fnet = 2iAB

we aslo use Fnet = 2Niab where N is no. of turns

here N =1

so Force   = 2iaB
======================================

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---