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I solved part a) of the question but I don\'t know how to do part b). If anyone

ID: 1283844 • Letter: I

Question

I solved part a) of the question but I don't know how to do part b). If anyone could explain step by step how to get answers for b), that would be greatly appreciated.

a)What is the thermal energy of a penny at a temperature of 291 K? The penny weighs 1 gram and is composed mainly of copper, which has an atomic weight of 63 g/mol.

>>>>>Ans:115.208

b) From what height would a penny have to be dropped in order to gain a center-of-mass energy equal to its thermal energy, as calculated above?

Explanation / Answer

center of mass energy here means kinetic energy if I am not mistaken.

KE= 0.5*m*v^2=115.208

v= 480m/s

to gain this velocity on dropping the distance of fall is given as.

v^2=u^2+2gs

here u=0.

s=v^2/2g=11.75km