The flux through a loop of wire changes uniformly from + 32Wb to -18Wb in 1.3ms.
ID: 1284168 • Letter: T
Question
The flux through a loop of wire changes uniformly from + 32Wb to -18Wb in 1.3ms. What is the significance of the negative number attached to the final flux value? What is the average induced emf in the loop? Express your answer using two significant figures. The flux through a loop of wire changes uniformly from + 32Wb to -18Wb in 1.3ms. If you wanted to double the average induced emf by changing only the time, what would the new time interval be? Express your answer using two significant figures. If you wanted to double the average induced emf by changing only the final flux value, what would it be? Express your answer using two significant figures.Explanation / Answer
part A> flux flux is oppositet o inital flux
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B. avg emf e = NAdB/dt = d(flux)/dt
emf e = (32-(-18)/0.0013
emf e = 38.4 KV or 38461.5 Volts
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as emf e = d(flux).dt
to double emf, time has to reduce by half
so tnew = 1.3/2 = 0.65 ms
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apply d(flux)/dt = 2* 38461.5* 1.3 ms
32-(-phi1) = 100
phi2 = 32-100 = -68 Wb