The flux of the electric field (24i + 30j + 16k) N/C through a 2.0 m^2 portion o
ID: 1527338 • Letter: T
Question
The flux of the electric field (24i + 30j + 16k) N/C through a 2.0 m^2 portion of the yz plane is: 32 N middot m^2/C 34 N middot m^2/C 42 N middot m^2/C 48 N middot m^2/C 60 N middot m^2/C Charge Q is distributed uniformly throughout an insulating sphere of radius R. The magnitude of the electric field at a point R/2 from the center is: Q/pi element_0 R^2 Q/8 pi element_0 R^2 3Q/4 pi element_0 R^2 Q/4 pi element_0 R^2 none of these A cylinder has a radius of 2.1 cm and a length of 8.8 cm. Total charge 6.1 times 10^-7 C is distributed uniformly throughout. The volume charge density is: 5.3 times 10^-5 C/m^3 5.3 times 10^-5 C/m^2 8.5 times 10^-4 C/m^3 5.0 times 10^-3 C/m^3 6.3 times 10^-2 C/m^3Explanation / Answer
The i vector is normal to the Electric field therefore 24 i to the yz plane.
Flux =EA. =24 x 2 = 48 Nm2/C