Two batteries with emf emf 1 and emf 2, with internal resistances r1 and r2 resp

Question

Two batteries with emf emf 1 and emf 2, with internal resistances r1 and r2 respectively, are connected as shown in the diagram below. (Assume e m f1 = 12 V and r1 = 1 ohm.)

(b) Find the terminal voltage of each battery.
V1 = V
V2 = V

magnitude     A direction = counterclockwise Two batteries with emf emf 1 and emf 2, with internal resistances r1 and r2 respectively, are connected as shown in the diagram below. (Assume e m f1 = 12 V and r1 = 1 ohm.) epsilon2 = 25.0 V and r2 = 0.40 ?. magnitude A direction = counterclockwise (b) Find the terminal voltage of each battery. V1 = V V2 = V a) Calculate the magnitude and indicate the direction of flow of current in the figure shown above.

Explanation / Answer

E2-E1 = I*(1+0.4)

I = 9.2857

clockwise

b) V1 = 12+9.2857 = 21.28

V2 = 25-.4*9.2857 = 21.28

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