Part A Find the position of the image of the arrow formed by paraxial rays incid

Question

Part A

Find the position of the image of the arrow formed by paraxial rays incident on the convex surface.

Part B

Find the height of the image formed by paraxial rays incident on the convex surface.

24.The left end of a long glass rod 8.00cm in diameter and with an index of refraction of 1.60 is ground and polished to a convex hemispherical surface with a radius of 4.00cm . An object in the form of an arrow 1.60mm tall, at right angles to the axis of the rod, is located on the axis 24.5cm to the left of the vertex of the convex surface.

Part A

Find the position of the image of the arrow formed by paraxial rays incident on the convex surface.

Part B

Find the height of the image formed by paraxial rays incident on the convex surface.

|y?| = mm 24.The left end of a long glass rod 8.00cm {rm mm} |y'| = mm {rm cm} to the left of the vertex of the convex surface. Part A Find the position of the image of the arrow formed by paraxial rays incident on the convex surface. Part B Find the height of the image formed by paraxial rays incident on the convex surface. |y?| {rm mm} tall, at right angles to the axis of the rod, is located on the axis 24.5cm {rm cm} . An object in the form of an arrow 1.60mm {rm cm} in diameter and with an index of refraction of 1.60 is ground and polished to a convex hemispherical surface with a radius of 4.00cm

Explanation / Answer

1/20.0 +1.6/s' = (1.6-1)/4
0.05 + 1.6/s' = 0.15
1.6/s' = 0.1
s' = 16cm

Magntifcation = image height/object height = image distance/object diatance = s'/s
y'/1.6 = 16/24.5
y' = 1.04mm

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