Part A Find the magnitude of the magnetic field at the point halfway between the

Question

Part A

Find the magnitude of the magnetic field at the point halfway between the wires.

Correct

Part B

Correct

Part C

Find the magnitude of the magnetic field at point 20 cm to the right of the wire on the right.

26.67•10?7

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Part D

What is its direction?

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Part E

Find the magnitude of the magnetic field at the point 20 cm above from the midpoint. (That is, go to the point in between the two wires- so 5 cm from either wire- in the diagram, and then move "upwards" in the diagram (not out!) by 20 cm.)

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Part F

The figure below shows two long, straight, parallel wires which each carry a curren of 4.00 A. They are 10.0 cmapart. (Figure 1) .

Part A

Find the magnitude of the magnetic field at the point halfway between the wires.

B = 0 T

Correct

Part B

What is its direction? to the left to the right upward downward -no field

Correct

Part C

Find the magnitude of the magnetic field at point 20 cm to the right of the wire on the right.

B =

26.67•10?7

T

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Part D

What is its direction?

to the left to the right upward downward no field

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Part E

Find the magnitude of the magnetic field at the point 20 cm above from the midpoint. (That is, go to the point in between the two wires- so 5 cm from either wire- in the diagram, and then move "upwards" in the diagram (not out!) by 20 cm.)

B = T

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Part F

What is its direction? to the left to the right upward downward no field

Explanation / Answer

B=B1+B2

B= Mu0*I/2*pi*r

B1 = Mu0*4/2*pi*0.2

B2 = Mu0*4/2*pi*0.2

B = Mu0*4/2*pi (1/0.2+1/0.3)

B = 66.64 *10^-7 T

E)

r = sqrt(20^2+5^2) = 20.61 cm

B = 2*Mu0*4/2*pi*0.2061 * sin 60, X- Components will cancel , Both Y-Components would remain, angle is 60 degrees

B = 67.23 *10^-7 T, along direction of current

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