The railway of a train is shown in Fig. 6-41 (h1 = 37 m, h2 = 15 m, h3 = 20 m).
ID: 1285482 • Letter: T
Question
The railway of a train is shown in Fig. 6-41 (h1 = 37 m, h2 = 15 m, h3 = 20 m). The train passes point 1 with a speed of 2.20 m/s. If the average force of friction is equal to 14% of its weight, with what speed will the train reach point 2? The distance traveled is 55.0 m.
The railway of a train is shown in Fig. 6-41 (h1 = 37 m, h2 = 15 m, h3 = 20 m). The train passes point 1 with a speed of 2.20 m/s. If the average force of friction is equal to 14% of its weight, with what speed will the train reach point 2? The distance traveled is 55.0 m.Explanation / Answer
Let the slope be an inclined plane approximately,
a= angel of inclination,
F=mgsin(a)-frictional force;
F=mgsin(a)-0.14*mg;
ma=mgsin(a)-0.14mg;
a=g*sin(a)-0.14*g;
sin (a) = h1/(distance travelled) =37/55;
=>a=g(37/55)-0.14*g;
=>a=0.537*g;
=>a=5.22 m/s^2;
(v^2)-(u^2)=2*a*s;
(v^2)=(2.2^2)+(2*5.22*55);
(v^2)=579.04;
v=24.063 m/s.