Playing shortstop, you pick up a ground ball and throw it to second base. The ba

Question

Playing shortstop, you pick up a ground ball and throw it to second base. The ball is thrown horizontally, with a speed of 26 m/s, directly toward point A. When the ball reaches the second baseman 0.45 s later, it is caught at point B. (Neglect air resistance.)

(a) How far were you from the second baseman?
m

(b) What is the distance of vertical drop, AB?
m

Playing shortstop, you pick up a ground ball and throw it to second base. The ball is thrown horizontally, with a speed of 26 m/s, directly toward point A. When the ball reaches the second baseman 0.45 s later, it is caught at point B. (Neglect air resistance.) (a) How far were you from the second baseman? m (b) What is the distance of vertical drop, AB? m

Explanation / Answer

Horizontal distance = 26 m/s x 0.45 s
= 11.7 m

Horizontal speed doesn't change because there is no horizontal force to change it.

Horizontal drop = H = 1/2 x 9.81 x (0.45)^2
=.99225 m

(Gravity makes it sink by this height H, so you use s = ut + (1/2)gt^2
Initially. there is no downward velocity, so u = 0.
Take downward acceleration of free fall, g = 9.81 m s^-2)

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