Two balls, of masses m A = 36 g and m B = 64 g are suspended as shown in Figure

Question

Two balls, of masses mA = 36 g and mB = 64 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60 angle with the vertical and released.

(a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)
m/s
(b) What is the velocity of each ball after the elastic collision?

(c) What will be the maximum height of each ball (above the collision point) after the elastic collision?

ball A   m/s ball B m/s Two balls, of masses mA = 36 g and mB = 64 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60½ angle with the vertical and released. Figure 7-44 (a) What is the velocity of the lighter ball before impact? (Take the right to be positive.) m/s (b) What is the velocity of each ball after the elastic collision? ball A m/s ball B m/s (c) What will be the maximum height of each ball (above the collision point) after the elastic collision? ball A m ball B m

Explanation / Answer

a) Vai = ?(2gh) = ?(2g*.15) = 1.715 m/s
b) Vcm = Vai*mA/(mA+mB) = .6173 m/s
uA = Vai - Vcm = 1.098 m/s
uB = Vcm = .6173 m/s

vA = Vcm - uA = -.4807 m/s
vB = Vcm + uB = 1.2346 m/s

c) Ha = vA

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