Part A Find v 2 v 1, the ratio of the velocity v 2 of the two-block system after

Question

Part A

Find v2v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision.

Express your answer numerically using three significant figures.

Part B

Find v3v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions.

Express your answer numerically using three significant figures.

A block of mass m1 = 1.60kg moving at v1 = 2.00m/sundergoes a completely inelastic collision with a stationary block of mass m2 = 0.100kg . The blocks then move, stuck together, at speed v2. After a short time, the two-block system collides inelastically with a third block, of mass m3 = 2.70kg , which is initially at rest. The three blocks then move, stuck together, with speed v3.(Figure 1) Assume that the blocks slide without friction. Part A Find v2v1, the ratio of the velocity v2 of the two-block system after the first collision to the velocity v1 of the block of mass m1 before the collision. Express your answer numerically using three significant figures. Part B Find v3v1, the ratio of the velocity v3 of the three-block system after the second collision to the velocity v1 of the block of mass m1 before the collisions. Express your answer numerically using three significant figures.

Explanation / Answer

1)
P1 = P2
m1*v1 = (m1+m2)*v2 ?
v2/v1 = m1/(m1+m2) = 1.6/(1.6+0.1) = 0.941

2)
P1 = P3
m1*v1 = (m1+m2+m3)*v3 ?
v3/v1 = m1/(m1+m2+m3) = 1.6/(1.6+0.1+2.7) =0.3636

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