Consider the rods plus disc system shown in the Figure. The rod has a length L =
ID: 1288967 • Letter: C
Question
Consider the rods plus disc system shown in the Figure. The rod has a length L =0.70 m, and mass M = 0.240kg. The large disc has a radius of R = 0.180m and mass m=0.720kg. The second disk should be treated as a point mass of 0.360kg. It is glued to the rod at position X = 0.25m. The system behaves as a compound pendulum that oscillates about pivot point P. The pivot is at P where the tip of rod rod meets with one end of the disk. Assume that the disc and rod have uniform mass distributions. a) Find how far below P is the center of mass of the rods and disks system. Answer in units of m. b) Find the moment of inertia of one of the rod, in units of kgm^2, as it freely rotates about the pivot point P. c) Find the moment of inertia of the disk (the large disk), in units of kgm^2, about its center of mass. d) Find the moment of inertia of the disk (the large disk), in units of kgm^2, as it freely rotates about the pivot point P. e) Find the moment of inertia of the whole system, in units of kgm^2, as it freely rotates about the pivot point P.Explanation / Answer
a. 2.3 m from P
b. 0.0392
c. 0.01164
d. 0.034992
e. 0.096692