Please show work and explain. Answer is already given. Thank You. Light in air (

Question

Please show work and explain. Answer is already given. Thank You. Light in air (n 1.0) enters a fiber optic cable (of material with 1.28) where it goes through total internal reflection as it travels down the cable. 1) What is the minimum angle e that it must strike the walls of the cable to undergo total internal reflection? 40.1 degrees a) 44.9 degrees 48.2 degrees degrees el 53.0 degrees be at thi d ab 40.1 degrees 44.9 degrees 48.2 degrees degrees S3.0 degrees 3) Compare the two angles e and B in the above diagram? dD It depends on index of refraction of the cable. g It depends on the initial angle entering the cable. An object is placed 10.0 cm in front of a mirror. The mirror produces an upright magnified image that is 3 times bigger than the object. 4) What type of mirror is it? a) A concave mirror with focal length less than 10 cm. Aconcave mirror with focal length greater than 10 cm. convex mirror with focal length less than 10 cm. duA convex mirror with focal length greater than 10 cm. e) This could happen with either a concave or a convex mirror. 5) How far from the mirror is the image? (Give the magnitude of this distance.) 3.33 cm. b 667 cm 15 cm 30 cm

Explanation / Answer

1) n2*sin theta = 1*sin 90

theta = 51.4

2) n1*sin alfa = n2*sin (90- theta)

1*sin alfa = 1.28*sin(90-51.4)

alfa = 53

3) theta = beta

4) -S'/S = 3=====S' = -30 cm

1/S - 1/S' = 1/f

1/10 - 1/30 = 1/f

f = 15 cm

a concave mirror with focal length greater than 10 cm

5) S'= 3S = 30 cm

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