Part A What is the magnitude of the induced current? Part B What is the directio
ID: 1303116 • Letter: P
Question
Part A
What is the magnitude of the induced current?
Part B
What is the direction of the induced current?
clockwise
counterclockwise
no direction
Part C
Later the loop is fully in the field, still moving at 33cm/s . What is the magnitude of the induced current?
Part D
What is the direction of the induced current?
clockwise
counterclockwise
no direction
Part E
Eventually the loop begins to emerge from the field, still at 33cm/s . What is the magnitude of the induced current?
Part F
What is the direction of the induced current?
clockwise
counterclockwise
no direction
Explanation / Answer
induced EMF = -d(BA)/dt
dA/dt = .08*dl/dt = .08*v
E = -B*.08*v
= - .02244V
I = 5.61 mA
b)
Faraday