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Part A What is the magnetic field B at point a in the figure(Figure 1) ? Give yo

ID: 1545799 • Letter: P

Question

Part A

What is the magnetic field B  at point a in the figure(Figure 1) ? Give your answer in component form.

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Bx, By =

Part B

What is the magnetic field B  at point b in the figure? Give your answer in component form.

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Part C

What is the magnetic field B  at point c in the figure? Give your answer in component form.

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Bx, By =

Part B

What is the magnetic field B  at point b in the figure? Give your answer in component form.

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Bx, By =

Part C

What is the magnetic field B  at point c in the figure? Give your answer in component form.

Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Bx, By = y cim. 10 A Long wires 0 x (cm) 10 A

Explanation / Answer

(a)

distance of point a from top wire,

d = sqrt [(0.01)^2 + (0.01)^2] = 0.01414 m

magnetic field at point a due top wire,

Btop = u0*l / 2*pi*d = 4*pi*10^(-7)*10 / 2*pi*0.01414

Btop = 1.414*10^(-4) T

distance of point a from top wire, d = 0.01414 m

Bbottom = 1.414*10^(-4) T

net magnetic field at point a,

Ba = Btop + Bbottom

Ba = 1.414*10^(-4)*cos45 i - 1.414*10^(-4)*sin45j + 1.414*10^(-4)*cos45 i + 1.414*10^(-4)*sin45 j

Ba = 2*1.414*10^(-4)*cos45

Bx , By = 1.99*10^(-4) i T , 0 j

(b)

magnetic field at point b due to top wire,

Btop = u0*l / 2*pi*d = 4*pi*10^(-7)*10 / 2*pi*0.01

Btop = 2*10^(-4) T

Bbottom = 2*10^(-4) T

Net magnetic field at point b,

Bb = Btop i + Bbottom j

Bb = 2*2*10^(-4)

Bx , By = 4*10^(-4) i T , 0 j

(c)

distance of point c from top wire,

d = sqrt [(0.01)^2 + (0.01)^2] = 0.01414 m

magnetic field at point c due top wire,

Btop = u0*l / 2*pi*d = 4*pi*10^(-7)*10 / 2*pi*0.01414

Bbottom = 1.414*10^(-4) T

net magnetic field at point c,

Bc = Btop + Bbottom

Bc = 1.414*10^(-4)*cos45 i - 1.414*10^(-4)*sin45j + 1.414*10^(-4)*cos45 i + 1.414*10^(-4)*sin45 j

Bc = 2*1.414*10^(-4)*cos45

Bx , By = 1.99*10^(-4) i T , 0 j

Answer