Please let me know how to do this. I did it myself and got .96 as a collision ti

Question

Please let me know how to do this. I did it myself and got .96 as a collision time. ball 2 is dropped, ball 1 is thrown up at a velocity of 1. Please explain...Thank you

Relative motion of free falling balls Data: v0 = 1 m/s, H = 10 m, ay = -g Find: Time of collision t; Position of collision y; What should be H in order v.,(t)=0. Solution: Relative velocity of the balls is v0 for they have the same acceleration ay= -g leftarrow t = H/v0 Eq.(3) for 2nd ball yields y = H - (1/2)gt2 = H - gH2/(2v02) Eq.(1) for 1st ball yields v1 = v0 - gt = v0 - gH/v0, hence, for v1=0 we find H = v02/g

Explanation / Answer

lets time t taken

for ball dropped H= 1/2 g t2

for ball thrown upward 10 - H = ut + 1/2 g t2

t= 0.9512 sec

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