Part A Four identical bulbs are shown in the circuit in (Figure 1) . With the sw
ID: 1310381 • Letter: P
Question
Part A
Four identical bulbs are shown in the circuit in (Figure 1) . With the switch open, bulbs 1, 2, and 3 are equally bright and bulb 4 is dark. How does the brightness of bulbs 1, 2, and 3 change when the switch is closed?
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Part B
Four identical bulbs are shown in the circuit in (Figure 1) with the switch open. How does the brightness of bulbs 1, 3, and 4 change when the switch is closed?
Part C
If a quantity you calculated has units of A
a.) 1 and 3 get brighter and 2 gets dimmer. b.) 1, 2, and 3 stay the same. c.) 1, 2, and 3 all get brighter. d.) 1 and 2 stay the same and 3 gets brighter. e.) None of these is correct.Explanation / Answer
A. when switch closed overall circuit resistance will become less so current from battery will be more.
So 1 ,3 wil get brighter. but v=current thorugh 2 will be less because some current will go through 4. so 2 will become dimmer
ans a. is correct.
B.current thorugh 3 will be same as V across it doesnt change and so the current. 1 and 2 comes in parallel so current through that path increases. So current thorugh 4 will be more and 4 becomes brighter.current through 1 got diverted and it will become dimmer.
ans A for it.
C. A. s means product of current and time which is charge.