The figure below shows two balls, m1 and m2 of the same mass. Ball 1 starts from
ID: 1313092 • Letter: T
Question
The figure below shows two balls, m1 and m2 of the same mass. Ball 1 starts from rest and slides down a frictionless slide from a height H from the floor. Ball 2 is dropped from rest at the same time from the same height. At height h ball 1 falls off the incline. For each of the following statements select the correct option. The velocity of ball 2 when it is at height h is greater than the velocity of ball 1 when it is also at height h. The time it takes for ball 1 to fall from h to the floor is the time it takes ball 2 to fall from h to the floor. The time it takes for ball 1 to slide from H to h is the time it takes ball 2 to fall the same vertical distance. The maximum height that ball 2 bounces up from the floor is the maximum height that ball 1 bounces from the floor. (Assume no loss in energy.) The kinetic energy of ball 1 when it is at height h is the kinetic energy of ball 2 when it is also at height h.Explanation / Answer
1. velocity of both balls are same (equal) as both are released frim the same height and there is no friction in the path of m1. hence from energy conservation , initially they had the same potential energy m*g*H , at height h , they have potential energy = m*g*h
=> K.E= m*g*(H-h)= 0.5*m*v^2
. hence they have the same velocity
2. greater than because only a part of the total velocity is the vertical velocity for m1 while the total velocity is vertical for m2
3. greater than because the distance travelled by the m1 is more than m2 as m1 has to travel along the hypotenus which is hreater than the height.
4. greater than because m2 has all velocity in the vertical componenet only . hence it's vertical velocity is greater than that of m1.
5.equal to (already explained in 1)