For the circuit to the right, consisting of three ideal batteries and three idea
ID: 1317405 • Letter: F
Question
For the circuit to the right, consisting of three ideal batteries and three ideal resistors, calculate the current through point P. Let the sign of the current correspond to its direction, with "up" being positive.
For the circuit to the right, consisting of three ideal batteries and three ideal resistors, calculate the current through point P. Let the sign of the current correspond to its direction, with "up" being positive. , -29.5 V, £.-22.5 V, ,-28.5 V Ri=5.10 kQ, R,-18.5 kQ, R,-5.50 k Number - .997 MAExplanation / Answer
Let I1 ,I2 and I3 are the currents through R1,R2 and R3 respectively.
Apply KVL in the left loop,
-I1*R1 + E1 - E2 -I2*R2 = 0
-3400*I1 + 22 - 10.5 - 12500*R2 = 0
3400*I1 + 12500*I2 = 11.5 ----(1)
Apply KVL in right loop,
E3 - I3*R3 - E2 - I2*R2 = 0
31.5 - 2500*I3 - 10.5 - 12500*I2 = 0
12500*I2 + 2500*I3 = 21 ----(2)
at the junction,
I1 + I3 = I2 ----(3)
on solving the equations 1,2 and 3
we get
I1 = -1.1 mA
I2 = 1.2 mA
I3 = 2.3 mA
so, I1 = -1.1 mA (current through point P)<<<<<<<<---------------Answer