For the circuit to the right, consisting of three ideal batteries and three idea

Question

For the circuit to the right, consisting of three ideal batteries and three ideal resistors, calculate the current through point P. Let the sign of the current correspond to its direction, with "up" being positive.

E1=34V E2=18V E3=36V

R1=2500 ohm R2=21500 ohm R3=3250 ohm

For the circuit to the right, consisting of three ideal batteries and three ideal resistors, calculate the current through point P. Let the sign of the current correspond to ts direction, with "up" being positive. e,-34.0 e,-34.0 v, v. E,-18.0 '= 18.0 v, e,-36.0 v V, 36.0 V R,-2.50 ko. R2 = 21.5 kQ, R3 = 3.25 k Number mA

Explanation / Answer

Given:

E1=34V E2=18V E3=36V

R1=2500 ohm R2=21500 ohm R3=3250 ohm

We need to find the total current flowing through point P,

For that we need to calculate the totoal resistant in the circuit.

R1 and R2 are in parallel .

So R = 1/R1 + 1/R2 = 1/2500 + 1/21500 = 0.0004 ohm

and R and R3 will be in series,

So final R = 0.0004 + 3250

R = 3250.0004 ohm

now V = E1 +E2 +E3 = 34 + 18 + 36 = 88 Volt

So,

the current will be ,

I = V / R

I = 88 / 3250.0004

I = 0.027 A

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