The figure here shows an overhead view of three horizontal forces acting on a ca
ID: 1324918 • Letter: T
Question
The figure here shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.90 N, F2 = 3.80 N, and F3 = 10.0 N, and the indicated angles are ?2 = 50.0 ? and ?3 = 31.0 ?. What is the net work done on the canister by the three forces during the first 4.20 m of displacement?
The figure here shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but that now moves across a frictionless floor. The force magnitudes are F1 = 2.90 N, F2 = 3.80 N, and F3 = 10.0 N, and the indicated angles are ?2 = 50.0 ? and ?3 = 31.0 ?. What is the net work done on the canister by the three forces during the first 4.20 m of displacement?Explanation / Answer
W (net)=F*d
F= magnitude of net force on canister
d=displacement of canister
F= sqrt.(Fx^2+Fy^2)
Fx= x component of net force
Fx = -2.9 - 3.8sin(50) + 10cos(31) = 2.96 N
Fy = y component of net force
Fy = -3.8cos(50) + 10sin(31) = 2.71 N
F = sqrt.( 2.96^2 + 2.71^2 ) = 4.013 N
W (net) = 4.013 N * 4.2 m = 16.855 J