Problem 18.55 For the capacitor network shown in (Figure 1), are potential diffe
ID: 1327172 • Letter: P
Question
Problem 18.55 For the capacitor network shown in (Figure 1), are potential difference across ab is 28 V. Part A Find the total charge stored in this network. Express your answer in microcoulombs to one decimal plane. Part B Find the Marge on the 150 nF capacitor. Express your anew in microcoulombs to one decimal pin. Part C Find me charge on the 120 nF capacitor. Express your answer in microcoulombs to one decimal place. Part D Find me total energy stored In the network. Express your answer In microjoules to one decimal place. Part E Find me energy stored in the 150 nF capacitor. Express your answer in microjoules to one decimal place.Explanation / Answer
A) net capacitance is Cnet = C1*C2/(C1+C2) = (150*120)/(150+120) = 66.67 nF
total charge stored is Qnet = Cnet *V = 66.67*10^-9*28 = 1866.67*10^-9 = 1.8667 uC
B) charge on the 150 nF capacitor is Q1 = 1.8667 uC
C) charge on the 120 nF cpacitor is Q2 = 1.8667 uC
D) energy sotred is U = 0.5*Cnet*V^2 = 0.5*66.67*10^-9*28*28 = 26.134*10^-6 J = 26.134 uJ
E) Energy stored in 150 nF is Q^2/(2*C) = (1.8667*1.8667)*10^-12/(2*150*10^-9) = 11.61 uJ