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Please can someone help me with both of these. I keep getting a wrong number and

ID: 1327964 • Letter: P

Question

Please can someone help me with both of these. I keep getting a wrong number and cant find out why

A parallel-plate capacitor has capacitance Co = 2.00 pF when there is air between the plates. The separation between the plates is 1.80 (a) What is the maximum magnitude of chargeQ that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 x 104 V/m? (b) A dielectric with K- 2.50 is inserted between the plates of the capacitor, completely filling the volume between the plates. V/m? Now what is the maximum magnitude of charge on each plate if the electric field between the plates is not to exceed 3.00 x 104

Explanation / Answer

We know that the capacitence,c=q/v
E=30000 V/m
Seperation between the plates,d=1.8mm

So voltage needed to produce the electric filed intensity will be 1.8mm x 30000V/m = 54V.

A) So q=cv;
=2pFx54V
=108pC

B)So when we insert the dielectric, it will affect the capacitance of the capacitor; since it is directly proportional to capacitance

So the new capacitance will be 2.5x2pF=5pF.

Now it can store more charges...

q=5pFx75V
=375nC

2)

Energy stored in capacitor = U = 7.52 J
We know that the energy,U =(1/2)CV2

C =(eo)A/d

C*d=(eo)A=constant

C2d2=C1d1

C2=C1d1/d2

The separation between the plates is 3.45mm . The separation is decreased to 1.5 mm.

Initial separation between the plates =d1= 3.45mm .

Final separation = d2 = 1.50 mm
(A) if the capacitor was disconnected from the potential source before the separation of the plates was changed, charge 'q' remains same

Energy=U =(1/2)q2/C

U2C2 = U1C1

U2 =U1C1 /C2

U2 =U1d2/d1

Final energy = Uf = initial energy *d2/d1

Final energy = Uf =7.52 *1.50/3.45

(A) Final energy = Uf = 3.27J

B) If the capacitor remained connected to the potential source while the separation of the plates was changed, potential remains same.

Final energy = Uf =(1/2)CV2

Final energy = Uf =(1/2)[C1d1/d2]V2

Final energy = Uf =(1/2)[C1V2]d1/d2


Final energy = Uf = initial energy *d1/d2

Final energy = Uf =7.52 *3.45/1.50

Final energy = Uf =17.296 J