Suppose an electron traveling with speed v 0 = 1.00×10 7 m/s enters a uniform el

Question

Suppose an electron traveling with speed v0 = 1.00×107m/s enters a uniform electric field E , which is at right angles to v 0 as shown in the figure.(Figure 1)

Part A

At what angle will the electrons leave the uniform electric field at the end of the parallel plates (point P in the figure)? Assume the plates are 5.5 cm long and E = 5.1×103 N/C . Ignore fringing of the field.

Express your answer to two significant figures and include the appropriate units.

Ans VALUE AND UNITS

Suppose an electron traveling with speed v0 = 1.00×107m/s enters a uniform electric field E , which is at right angles to v 0 as shown in the figure.(Figure 1)

Part A

At what angle will the electrons leave the uniform electric field at the end of the parallel plates (point P in the figure)? Assume the plates are 5.5 cm long and E = 5.1×103 N/C . Ignore fringing of the field.

Express your answer to two significant figures and include the appropriate units.

Ans VALUE AND UNITS

Explanation / Answer

Here ,

acceleration of the electrons is a

using second law of motion

q *E = m*a

1.602 *10^-19 * 5.1 *10^3 = 9.1 *10^-31 * a

a = 8.97* 10^ 14 m/s^2

time taken for the elctron to pass ,

t = 0.055/(1 *10^7)

t = 5.5 *10^-9 s

Now , velocity in the direction of field , Vx = 5.5 *10^-9 * 8.97* 10^ 14

Vx = 4.93 *10^6 m/s

angle , theta = arctan(Vx/v0)

theta = arctan(0.493/1)

theta =26.3 degree

the electron makes 26.3 degree from it's initial velocity

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