Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Please answer question showing all work. Please see attached wo pure breeding pl

ID: 133210 • Letter: P

Question

Please answer question showing all work.    Please see attached wo pure breeding plants with the genotypes ddPP and DDpp are crossed together to generate l progeny with the genotype DdPp. FI individuals were testcrossed to a homozygous parental strain (ddpp). The following data were obtained: observed#of progeny Genotype DdPp Ddpp Ddpp ddPp Expected # of progeny 190 210 310 290 Total: 1000 A. In the table above, fill in the values for the expected number of progeny for each genotype based on the hypothesis that D and P are unlinked. B. What is the calculated ?2 value? C. How many degrees of freedom are there? D. Are D and P linked or unlinked? (Use the X2 table attached below). E. Briefly explain how the z2 analysis supports your conclusion. 0999 0.9959 .97505 1 0s 001 0.00s 2 0.002 01 0.02 . 13 02 136 455 23 230 10.532 33 826 s 0.210412 210 0531 1145 L.,620 4351 236 110 12.833 15086 16 750 20515 vya 0024 0072 0.24 0216 052 2.36 21 7.315 11.343 12.838 16.2 115 73.761 79.092 73.761 87.213 91.242 9604 114.314 134.813 141030 146.57 153.191 157.808 17.610 116 7.558 50.522 74558 ssos4 92134 %.958 115.334 135298 142.138147700 i54.)44 ise.smisuu 111?,356 81.353 75.356 s8.955 93036 97571 1163 l4 1X982 14.246148 829 is 496 100. 1461m ons 119 7s.ss5 83.018 7.955 90700 sau 9s707 1?134 ustasus,letnica, usmeie4ttm4u 120 77.753 83.852 77.755 91.573 95.205 100.524 119.334 140.233 145 567 152.213 158950 163548 17327

Explanation / Answer

Ans. a

O-E

b. chi square value = 14.4 + 6.4 + 14.4 + 6.4 = 41.6

c. degrees of freedom = 4 -1 = 3

d and e.

As tabulated chi square value = 7.315 (d.o.f = 3 and 0.05 level of significance) is lesser than calculated chi square value hence null hypotheis is rejectedi.e., there is a significant difference among the four groups which means the D and P are linked.

Genotype Observed(O) Expected(E)

O-E

(O-E)2 (O-E)2 / E DdPp 190 250 -60 3600 14.4 ddPp 210 250 -40 1600 6.4 Ddpp 310 250 60 3600 14.4 ddpp 290 250 40 1600 6.4