Map Presented by Physics open Stax sapling learning A person slaps her leg with

Question

Map Presented by Physics open Stax sapling learning A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.55 milliseconds from an initial speed of 5.25 m/s. What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.35 kg? Number Would the contact force be any different if the woman clapped her hands together, each with an initial speed of 5.25 m/s, if they come to rest in the same time interval as above? O It depends on the coefficient of friction between the two hands O No, because the second hand has zero momentum. O No, because the change in momentum for the first hand will be the same. O Yes, because the change in momentum is different O Yes, because the initial momentum of the system will be different due to the second hand A Previous Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

Here ,

initial speed , u = 5.25 m/s

t = 2.55 ms

force exerted = change in momentum/time

force exerted = 1.35 * (5.25/.00255)

force exerted = 2779 N

the force exerted on the leg is 2779 N

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yes , because the initial momentum of the system will be difference due to second hand

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