Assuming negligible friction, how many forces are acting on the cart as it slide

Question

Assuming negligible friction, how many forces are acting on the cart as it slides down an incline that makes an angle a relative to the horizontal? Name those forces. Which of those forces will result in work that is equal to zero? Why are they zero? (draw the direction of the force and the direction of the displacement). For a cart of mass m, and an incline of a, and a travel distance d along the slope, find the net work done on the cart. Adjustable cart track Protractor Cart Two Photogates Science Workshop 500

Explanation / Answer

Here ,

1) for no friction present

the forces on the cart is

Normal force , gravity from earth

2)

as the normal force is always perpendicular to the direction of motion

work done by normal force is zerp

3)

Net work done = work done by gravity

Net work done = m * g * d * sin(alpha)

the Net work done = m g d * sin(aplha)

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