Consider an object of mass B 75 kg. Assume that it\'s made up of equal numbers o

Question

Consider an object of mass B 75 kg. Assume that it's made up of equal numbers of protons, neutrons, and electrons. Remember that protons and neutrons each have the same mass individually, namely 1.7x10 kg; electrons have negligible mass by comparison; and that the charge of an individual proton (or electron) has magnitude 1.6 x 1019 C. (a) How many protons does the object contain? Answer: 10 Protons (b) Now imagine taking all the protons out of the object and stuffing them into a box. Also take all of the electrons out of the object and stuff them in a second box. How much charge is contained in each box? Answer: x 10-C (c) Now imagine separating the two boxes -the one containing all the protons, the other containing all the electrons. Let's put them at a distance of C.83m from one another. What will be the strength of the force of attraction between the two boxes? Answer:x10N x 10 N

Explanation / Answer

givne mass of the object is 7.5 kg and mass of proton or neutron is 1.7*10^-27 kg

givne that the mass of the electron can be neglected

now the no of protons and neutrons and electrons are equal in number so the object contains

7.5/ (2*1.7*10^-27)

n = 2.2055*10^27 protons and neutrons and electrons ( because electrons mass is neglected any number of electrons mass does not affect here)

b) each box contains 2.2055*10^27*1.6*10^-19 C of charge = 3.5288*10^8 C (+,-)

c) couloumb force of attraction between the boxes is

F= Kq1*q2/r^2

= -9*10^9*3.5288*10^8*3.5288*10^8/(8.3*8.3)

= -1.6268*10^25 N

d) work done is equal to the potential enerygy of the charges separated by r distance is

U= K*Q1*Q2/r

= 9*10^9*3.5288*10^8*3.5288*10^8/0.5

= 224.14*10^25 J

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