In the figure below, stick figure O (the object) stands on the common central ax
ID: 1372780 • Letter: I
Question
In the figure below, stick figure O (the object) stands on the common central axis of two thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 (mounted in box 1) is a converging lens, O is at object distance p1 = 6.00 cm, and the distance between the lens and its focal point is 10.0 cm. Lens 2 (box 2) is a diverging lens at distance d = 16.0 cm, and the distance between the lens and its focal point is 10.0 cm. What is the overall magnification of the system?
In the figure below, stick figure O (the object) stands on the common central axis of two thin, symmetric lenses, which are mounted in the boxed regions. Lens 1 (mounted in box 1) is a converging lens, O is at object distance p1 = 6.00 cm, and the distance between the lens and its focal point is 10.0 cm. Lens 2 (box 2) is a diverging lens at distance d = 16.0 cm, and the distance between the lens and its focal point is 10.0 cm. What is the overall magnification of the system?Explanation / Answer
For the first lens...
1/f = 1/p + 1/q
1/6 = 1/10 + 1/q
q = 15 cm
Sicne the lenses are 16 cm apart, for the diverging lens we get
1/f = 1/p + 1/q
1/-10 = 1/1 + 1/q
q = -.909 cm
Total M = -q/p times -q/p
M = -15/6 times -(-.909)/1
M = -2.27