In the figure, block A (mass 1.4 kg) slides into block B (mass 2.9 kg), along a
ID: 1373052 • Letter: I
Question
In the figure, block A (mass 1.4 kg) slides into block B (mass 2.9 kg), along a frictionless surface. The directions of velocities before and after the collision are indicated; the corresponding speeds are vAi = 5.5 m/s, vBi = 2.2 m/s, and vBf = 4.0 m/s. What is velocity vAf (including sign, where positive denotes motion to the right)?
In the figure, block A (mass 1.4 kg) slides into block B (mass 2.9 kg), along a frictionless surface. The directions of velocities before and after the collision are indicated; the corresponding speeds are vAi = 5.5 m/s, vBi = 2.2 m/s, and vBf = 4.0 m/s. What is velocity vAf (including sign, where positive denotes motion to the right)?Explanation / Answer
By Conservation of momentum
mAVAi + mBVBI =mAVAf +mBVBf
1.4*5.5 +2.9*2.2 =1.4VAf+2.9*4
VAf=1.77 m/s