In the circuit shown in the figure (Figure 1) , E = 59.0V , R 1 = 38.0? , R 2 =

ID: 1377524 • Letter: I

Question

In the circuit shown in the figure (Figure 1) , E = 59.0V ,R1 = 38.0? , R2 = 27.0? , and L = 0.291H . Switch Sis closed at t=0.

Part A

Just after the switch is closed, what is the potential difference vab across the resistor R1?

Part B

Which point, a or b, is at a higher potential?

Part C

What is the potential difference vcdacross the inductor L?

Part D

Which point, c or d, is at a higher potential?

Part E

The switch is left closed a long time and then opened. Just after the switch is opened, what is the potential difference vab across the resistor R1?

Part F

Which point, a or b, is at a higher potential?

Part G

What is the potential difference vcdacross the inductor L?

Part H

Which point, c or d, is at a higher potential?

just after the switch is closed, the inductor will act like open circuit
a)
so Vab=59 volts
b) a is at higher potential

c)59 volts as there is no voltage drop across R2

d)c

e)if it is closed for a long time, the inductor will be saturated and shorted.

then current through L=59/27=2.185 A

now once the switch is opened , the current through R1=2.185 A, from b to a

then Vab=-38*2.185=-83.03 volts

f)b

g)0

h)both at same potential